2024年06月03日 建站教程
def chineseNumber2Int(strNum: str):
result = 0
temp = 1 # 存放一个单位的数字如：十万
count = 0 # 判断是否有chArr
cnArr = ['壹', '贰', '叁', '肆', '伍', '陆', '柒', '捌', '玖']
chArr = ['拾', '佰', '仟', '万', '亿']
for i in range(len(strNum)):
b = True
c = strNum[i]
for j in range(len(cnArr)):
if c == cnArr[j]:
if count != 0:
result += temp
count = 0
temp = j + 1
b = False
break
if b:
for j in range(len(chArr)):
if c == chArr[j]:
if j == 0:
temp *= 10
elif j == 1:
temp *= 100
elif j == 2:
temp *= 1000
elif j == 3:
temp *= 10000
elif j == 4:
temp *= 100000000
count += 1
if i == len(strNum) - 1:
result += temp
return result
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